tolong jawab dengan cara2 nya
[tex]2x + 5x = 28 \\ 7x = 28 \\ x = \frac{28}{7} = 4 \\ so = 2x = 2.4 = 8 \\ qo = 5x = 5.4 = 20 \\ \\ luas = \frac{1}{2} \times d1 \times d2 \\ 420 = \frac{1}{2} \times 28 \times d2 \\ 420 = 14d2 \\ d2 = \frac{420}{14} = 30 \\ po = 30 \div 2 = 15 \\ \\ ps = \sqrt{ {po}^{2} + {so}^{2} } = \sqrt{ {15}^{2} + {8}^{2} } \\ ps = \sqrt{225 + 64} = \sqrt{289} = 17 \\ \\ pq = \sqrt{ {po}^{2} + {qo}^{2} } = \sqrt{ {15}^{2} + {20}^{2} } \\ pq = \sqrt{225 + 400} = \sqrt{625} = 25 \\ \\ keliling \: pqrs \\ 2(ps + pq) \\ 2(17 + 25) \\ 2(42) \\ 84 \: cm [/tex]
•Tulis rumus-rumus yang dibutuhkan.
[tex]\text{Luas Layangan }=\frac{1}{2}×SQ×PR[/tex]
[tex]\text{Keliling Layangan }=PS+SR+RQ+QP[/tex]
•Tulis diketahui.
[tex]PO=(2a+3)cm[/tex]
[tex]SQ=28cm[/tex]
•Telaah [tex]SO:QO=2:5[/tex]
[tex]\text{Maka, }SO+QO=SQ\\2d+5d=7d\\SQ=28=7d[/tex]
maka d=4
[tex]2×d=SO\\SO=2×4=8\\5×d=QO\\QO=5×4=20[/tex]
Jawabannya 84 cm
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